ERJ Brainteaser: July
31 Jul 2026
For impressive answering throughout July, including tricky Q2 without any clues, it's congratulations to Bharat B Sharma of TWC Group, new holder of the Brainiac of the Month title
Question 4: X factor
1 = 1
2 = 2
3 = 6
4 = X
Answer: The Brainiac factor-y made short (and long) work of this one (Solutions below). Very well done to: Hans-Bernd Luechtefeld, consultant, Germany; Andy Longdon, technical sales manager, Ceetak Ltd, Bedford UK; John Bowen, BSc [Hons], CEng, MIMMM, consultant, Bromsgrove, UK; Bharat B Sharma, technical director TWC Group (Techno Waxchem & Rajsha Chemicals), Kolkata, India; Andrew Knox, Rubbond International, Ohé en Laak, The Netherlands; Kamila Staszewska, R&D / quality lead, Abcon Industrial Products Ltd, Cootehill, Co. Cavan, Ireland; Amparo Botella, responsible de Compras y Calidad, Ismael Quesada SA, Elche, Alicante, Spain; Roshan Samaranayaka, manager - research and development, Jafferjee Brothers Exports (Pvt) Ltd, Colombo, Sri Lanka; P J Swamy, managing director, Fores Elastomech India Pvt Ltd, Waluj , Aurangabad, Maharastra , India; Dr Kate Burns, senior technologist and regulatory officer, Prisma Colour Ltd, Birch Vale, High Peak, Derbyshire, UK; Sabit Karayel, R&D director, Ozka Lastik, Ba?iskele, Kocaeli, Turkey; and everyone else who had a go.
SOLUTIONS
Hans-Bernd Luechtefeld
The pattern is:
1 = 1 × 1 = 1
2 = 1 × 2 = 2
3 = 1 × 2 × 3 = 6
4 = 1 × 2 × 3 × 4 = 24
Ergo: 4! = 24.
Andy Longdon
Initially, two sequences spring to mind:
Right digit is the product of the previous and current left digits; 1x2=2, 2x3=6, 3x4=12, so X = 12
Or
Right digit is the product of the current left digit and the previous right digit; 2x1=2, 3x2=6, 4x6=24, so X = 24
John Bowen
This ia a Factorial progression:
1 = 1 x 1 = 1
2 = 2 x 1 = 2
3 = 3 x 2 x 1 = 6
4 = 4 x 3 x 2 x 1 = 24
and so on…
Bharat B Sharma
STAR ANSWER: Covers most angles…
I may be wrong but this question appears to be quite simple
X Factor -- or is it Factorial X??? – which is filling/fitting - 100% in the sequence
- n! = nx(n-1)x(n-2)x…… x(n-n+1)
- 1!= 1 =1
- 2!= 2x1 =2
- 3!= 3x2x1 =6
- 4!= 4x3x2x1 =24
- 5! =5x4x3x2x1=120
- So here the sequence is 1, 2 , 6, 24,120 (answer could be 21)
Mathematically, there could be a few more models as the sequence has just begun with only three numbers and fourth number can be arrived based on other factors like
- Liner Pattern---
- 1
- 2= {(1x1)+1}
- 6{(2x2)+2}
- 21 {(3x6)+3)
- 88 {(4X21)+4}
- So here the sequence could be 1, 2 , 6, 21, 88 (answer could be 21)
- Perfect Square Difference Pattern
If you evaluate the differences between the numbers as growing perfect squares (\(1^2, 2^2, 3^2...\)): [1]
- 1 =1
- 1+12 = 2 =2
- 2+22 =2+4 =6
- 6+32 =6+9 =15
- 15+42 =15+16 =31
- So here the sequence could be 1, 2 , 6, 15, 31 (answer could be 15)
Andrew Knox
This sequence is the factorial of the numbers to the left of the equals sign, so, X is 4x3x2x1 = 24
Kamila Staszewska,
Factor-IAL is the answer (!)
1!=1
2!=1*2
3!=1*2*3=6
4!=1*2*3*4=24
Amparo Botella
I think the pattern is:
1=1!=1
2=2!=2x1=2
3=3!=3x2x1=6
4=4!=4x3x2x1=24
So X=24
Dr Kate Burns
1 = 1
2 = 2 (2x1)
3 = 6 (3x2x1)
4 = 24 (4x3x2x1)
I think the sequence this week is the factorials as shown.
New teaser on Monday
Question 3: Missing letters
…, _?_ , LXXXIX, CXLIV, CCXXXIII, CCCLXXVII, …
Answer: Venerunt, viderunt, vicerunt (see Solutions below): Bharat B Sharma, technical director TWC Group (Techno Waxchem & Rajsha Chemicals), Kolkata, India; John Bowen, BSc [Hons], CEng, MIMMM, consultant, Bromsgrove, UK; Hans-Bernd Luechtefeld, consultant, Germany; Andrew Knox, Rubbond International, Ohé en Laak, The Netherlands; Dr Kate Burns, senior technologist and regulatory officer, Prisma Colour Ltd, Birch Vale, High Peak, Derbyshire, UK; Kamila Staszewska, R&D / quality lead, Abcon Industrial Products Ltd, Cootehill, Co. Cavan, Ireland; Andy Longdon, technical sales manager, Ceetak Ltd, Bedford UK; Jose Padron, project coordinator, laboratory R&D, E2Metrix Canada Inc., Sherbrooke, Quebec, Canada; Amparo Botella, responsable de Compras y Calidad, Ismael Quesada SA, Elche, Alicante, Spain; Kamila Staszewska, R&D / quality lead, Abcon Industrial Products Ltd, Cootehill, Co. Cavan, Ireland; Andy Longdon, technical sales manager, Ceetak Ltd, Bedford UK. Well done to all and everyone else who had a go.
SOLUTIONS
Bharat B Sharma
The sequence appears to be of Roman Numbers—If we decode the Roman number, we get
- LXXXIX = 89
- CXLIV = 144
- CCXXXIII = 233
- CCCLXXVII = 377
Apparent Pattern
The resulting sequence (---, 89, 144, 233, 377)
89+144 = 233
144+233 = 377
Net number , accordingly could be 233+377 = 610
So earlier number (before 89 could be such that its addition will be 144 (144-89==55)
Sequence thus would be == 59, 89, 144, 233, 377,610 etc.
Now as the clues are in Roman numerals, let’s convert 55:
50 = L
- 5 = V
- 55 is LV
The missing letters in the series of numbers in Roman letters / Answer could be LV.
John Bowen
Translated into more familiar Arabic numerals, these become 89, 144, 233, 377, a Fibonacci series, ie each number is the sum of the previous two. So the previous 3 numbers are 21,34,55 or in Roman notation XXI, XXXIV, LV…
Hans-Bernd Luechtefeld
Result is LV (55).
Because:
LXXXIX, CXLIV, CCXXXIII, CCCLXXVII = 89, 144, 233, 377
Adding up 89+144 = 233, 144+233 = 377, etc.
So x+89 = 144, gives x = 55 resp. LV.
Dr Kate Burns
STAR ANSWER: Neat reply
This is the Fibonacci sequence written in Roman numerals. The missing number is LV (55).
Andrew Knox
The preceding number (in Roman numerals) is LV (55 in decimals) and preceding that would be XXXIV (34). See scribbles below.
Reasoning: Taking the differences between successive decimal number equivalents gives the previous number in decimals, which then needs converting back to Roman numerals.
Ancient Romans are still very confused when buying the correct sized underwear – in reference to the modern sizing system of L, XL, etc..
Jose Padron
STAR ANSWER: Nice practice run
Hello, this is the Fibonacci series written in Roman Numbers, so the answer is LV = 55
Just to practice my memory, here is the Fibonacci series from the beginning:
I = 1
II = 2
III = 3
V = 5
VIII = 8
XIII = 13
XXI = 21
XXXIV = 34
LV = 55
LXXXIX = 89
CXLIV = 144
CCXXXIII = 233
CCCLXXVII = 377
DX = 510
DCCCVII = 887
MCCCXCVII = 1397
Amparo Botella
The missing term is LV.
Converting the Roman numerals gives:
LXXXIX = 89
CXLIV = 144
CCXXXIII = 233
CCCLXXVII = 377
These numbers are consecutive terms in the Fibonacci sequence:
55, 89, 144, 233, 377, ...
The clue “I, II, III, V…” represents the first Fibonacci numbers written in Roman numerals:
I (1), II (2), III (3), V (5), VIII (8), XIII (13), XXI (21), XXXIV (34), LV (55), LXXXIX (89), ...
Kamila Staszewska
These are how ancient Romans would written the Fibonacci sequence
…, LXXXIX, CXLIV, CCXXXIII, CCCLXXVII that’s 89 ,144, 233, 377
55 is before this sequence so LV is the answer
Andy Longdon
Converting these Roman Numerals to modern numbers gives the sequence:
_?_, 89, 144, 233, 377
Which is a Fibonacci sequence where each number is the sum of the two numbers preceding it. Hence the number missing would be 144-89=55, which in Roman Numerals format is LV.
New teaser on Monday.
Question 2: You cannot be series! (#11)
_?_, _?_ 125, 2,401, 161,051, 4,826,809, ..
Clues: Prime, Power…
Email your answer: correct replies on Friday.
Bonus question: Find the link
Anaya, Cardini, Grey, Montagu, Wellesley...
Clues: Nachos, Caesar...
Answer: Well done to everyone who grappled with this tough teaser (and bonus Q). Coming out on top were: Bharat B Sharma, technical director TWC Group (Techno Waxchem & Rajsha Chemicals), Kolkata, India; Hans-Bernd Luechtefeld, consultant, Germany; Andrew Knox, Rubbond International, Ohé en Laak, The Netherlands; Dr Kate Burns, senior technologist and regulatory officer, Prisma Colour Ltd, Birch Vale, High Peak, Derbyshire, UK; Kamila Staszewska, R&D / quality lead, Abcon Industrial Products Ltd, Cootehill, Co. Cavan, Ireland; Andy Longdon, technical sales manager, Ceetak Ltd, Bedford UK;
SOLUTIONS
Bharat B Sharma
STAR ANSWER: Before any clues were issued
It appears to be a complex series—
There seems to be two Series chains working-
Base series of prime numbers – 2,3,5,7,
This series has exponential powers starting from 1, 2,3,4,5,6 etc.
So the sequence is:
Prime#1 (power 1); Prime#2 (power 2); Prime#3 (power 3); Prime#4 (power 4); Prime#5 (power 5); Prime#6 (power 6);
Which is 2 (power 1); 3 (power 2); 5 (power 3); 7 (power 4); 11 (power 5); 13 (power 6);
21, 32 53, 74 , 115 136
which is exactly 2, 9, 125, 2401, 161051, 4826809
… (with 2 and 9 being the missing two numbers of the series)
Bonus question
Anaya, Cardini, Grey, Montagu, Wellsley...
This was little easier as these were the family names of inventors /imitators of few common food & drinks stuffs
Clue Full Name Inventor / marketer / promoter of
- Anaya: Ignacio "Nacho" Anaya Nachos.
- Cardini: Caesar Cardini Caesar Salad.
- Grey: Charles Grey (2nd Earl Grey) Earl Grey tea.
- Montagu: John Montagu (4th Earl of Sandwich) Sandwich.
- Wellsley (Wellesley): Arthur Wellesley (1st Duke of Wellington) Beef Wellington.
Andrew Knox
Answer: the missing numbers to the left are 2, 9.
This sequence is that of consecutive prime numbers raised to the power of ever increasing factors beginning with 1, then 2, etc.. So 125 is 5^3, 2401 is 7^4, and the first two numbers in the sequence are 2^1 = 2, and 3^2 = 9.
Apologies, I had overlooked the bonus question: Since Wellesley is misspelled [since corrected] in the question, I thought Montague might be as well, and started to look for other Field Marshals... I had no idea that the Earls of Sandwich were called Montegu. The other chaps who apparently gave their names to food-related items were a Mexican chef called Ignaicio Anaya (Nacho's), Earl Grey (a Bergamot-flavoured tea) and Caesar Cardini (who came up with the Caesar salad).
Dr Kate Burns
The sequence this week is based on the prime numbers, where the first prime number is raised to the power 1, the second prime number to the power 2 and so on. As below, the missing numbers are 2, 9.
|
Sequence Number |
Prime Number |
Calculation |
Answer |
|
1 |
2 |
2^1 |
2 |
|
2 |
3 |
3^2 |
9 |
|
3 |
5 |
5^3 |
125 |
|
4 |
7 |
7^4 |
2401 |
|
5 |
11 |
11^5 |
161051 |
|
6 |
13 |
13^6 |
4826809 |
Hans-Bernd Luechtefeld
The answer is 2 (2 exponent 1) and 9 (3 exponent 2).
The series is defined by growing prime numbers, raised by an exponent which increases by 1 each time. The first figure given is 125 (5 exponent 3), so the next below is 3 exponent 2, etc.
Bonus question:
People whose names became associated with famous things resp. food/meals:
Ignacio "Nacho" Anaya → nachos
Caesar Cardini → Caesar salad
Charles Grey, 2nd Earl Grey → Earl Grey tea
John Montagu, 4th Earl of Sandwich → the sandwich
Arthur Wellesley, 1st Duke of Wellington → Beef Wellington
Kamila Staszewska
The pattern is prime numbers raised to increasing powers:
2^1 , 3^2, 5^3, 7^4, 11^5, 13^6
The answer is 2 and 9
Bonus
These seem to be are surnames of people which foods or dishes were named after(their first names or noble title they held:
Nacho(s) Anaya
Caesar (Salad) Cardini
Earl Gray (Tea)
John Montagu Earl of Sandwich
Arthur Wellesley Duke of Wellington – Beef Wellington
Andy Longdon
The number sequence is prime numbers to the power of their position in the prime number series, so the missing numbers are 1 and 9:
1^1 = 1
3^2 = 9
5^3 = 125
7^4 = 2,401
11^5 = 161,051
13^6 = 4,826,809
For the connection: Anaya, Cardini, Grey, Montagu, Wellesley
These are the surnames of people who have created or inspired famous foods that are named after them:
Ignacio (Nacho) Anaya (Nacho being Spanish nickname for Igancio)
Caesar Cardini (Caesar Salad)
Charles Grey (Earl Grey Tea)
John Montagu (the Earl of Sandwich)
Arthur Wellesley (Beef Wellington).
New teaser on Monday.
Question 1: Not double
109.4, 218.7, 437.4, 874.9, _?_.
Clues: Track, Man in picture, Distance…
Answer: Just a few Brainiacs on the right track this week, and fewer still reached the correct finishing line - 1640.4 yards (Solutions below): Andrew Knox, Rubbond International, Ohé en Laak, The Netherlands; John Coleman, membership manager, Circol ELT, Dublin, Ireland; Dr Kate Burns, senior technologist and regulatory officer, Prisma Colour Ltd, Birch Vale, High Peak, Derbyshire, UK; John Bowen, BSc [Hons], CEng, MIMMM, consultant, Bromsgrove, UK. But we also accept the alternative interpretations from: Bharat B Sharma, technical director TWC Group (Techno Waxchem & Rajsha Chemicals), Kolkata, India; Hans-Bernd Luechtefeld, consultant, Germany; Kamila Staszewska, R&D / quality lead, Abcon Industrial Products Ltd, Cootehill, Co. Cavan, Ireland. Well done to all and everyone else who had a go.
SOLUTIONS
Andrew Knox
These numbers appear to be distances in yards of athletics track events in metres, listed in ascending order and starting with 100 metres. The next distance therefore will be 1640.4 yards (1500 metres), which is indeed the first distance which is not exactly twice the previous distance.
Why the next distance is not 1600 metres is a good question, as this would then have been very close to one mile (which is 1609.3 metres). (Of course, working in furlongs (1/8th mile, or 10 chains) would have been even simpler, one furlong being 201.2 metres, and half a furlong being 100.6 metres).
John Coleman
This is the classic athletics track distances (100 m, 200 m, 400 m, 800 m) converted from metres to yards (1 m ≈ 1.09361 yd).
Therefore, the next distance is the 1,500m (not double!) which equates to our answer - 1,640.4yds.
Dr Kate Burns
This sequence is the length of short and medium-distance running races in yards. The next distance in standard running events is 1500 m, or 1640.4 yards.
109.4 yards = 100 m
218.7 yards = 200 m
437.4 yards = 400 m
874.9 yards = 800 m
1640.4 yards = 1500m
ALTERNATIVELY
BB Sharma
A simple pattern is visible in the main values:
109.4 × 2 = 218.8 → given 218.7 (−0.1)
218.7 × 2 = 437.4 – Given 437.4 (0)
437.4 × 2 = 874.8 → given 874.9 (+0.1)
So, the next number could follow double with sequence of ((−0.1); 0, +0.1 which can be +0.2) - (sequence as -0.1; 0; +0.1; +0.2……)
So the next number would be 2x874.9+0.2 = 1749.8 +0.2 = 1750
Answer is 1750.
Kamila Staszewska
The pattern is race distances 100m, 200m, 400m, 800m expressed in yards.
The last distance is 1600m = 1749.8yd
Hans-Bernd Luechtefeld
1,749.8
These figures correspond exactly to the lengths of the Olympic track events, converted from meters to yards (1 meter ≈ 1.09361 yards): 100 meters = 109.4 yards, 200 meters = 218.7 yards, 400 meters = 437.4 yards, 800 meters = 874.9 yards, 1,600 meters (4 laps around the stadium) = 1,749.8 yards.
New teaser on Monday.
